Intersection of a Sphere and a Coordinate Plane

Intersection of a Sphere and a Coordinate Plane

For sphere:

$$(x-a)^2+(y-b)^2+(z-c)^2=r^2$$

the intersection with the $$xy$$-plane is obtained by putting:

$$z=0$$

giving:

$$(x-a)^2+(y-b)^2+c^2=r^2$$

Usage

- Used to find the circular cross-section formed by a coordinate plane.