Intersection of a Line and a Plane
For line:
$$x=x_1+a\lambda$$
$$y=y_1+b\lambda$$
$$z=z_1+c\lambda$$
and plane:
$$Ax+By+Cz+D=0$$
substitution gives:
$$A(x_1+a\lambda)+B(y_1+b\lambda)+C(z_1+c\lambda)+D=0$$
Hence:
$$\lambda=-\frac{Ax_1+By_1+Cz_1+D}{Aa+Bb+Cc}$$
provided:
$$Aa+Bb+Cc\neq0$$
Usage
- Used to find the point where a line intersects a plane.
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