NTA JEE Main 7th January 2020 Shift 1

Instructions

For the following questions answer them individually

NTA JEE Main 7th January 2020 Shift 1 - Question 11


The current $$I_1$$ (in A) flowing through 1$$\Omega$$ resistor in the following circuit is:

NTA JEE Main 7th January 2020 Shift 1 - Question 12


A long solenoid of radius R carries a time $$(t)$$ dependent current $$I(t) = I_0 t(1 - t)$$. A ring of radius 2R is placed coaxially near its middle. During the time interval $$0 \le t \le 1$$, the induced current $$(I_R)$$ and the induced EMF $$(V_R)$$ in the ring change as:

NTA JEE Main 7th January 2020 Shift 1 - Question 13


Consider a circular coil of wire carrying constant current I, forming a magnetic dipole. The magnetic flux through an infinite plane that contains the circular coil and excluding the circular coil area is given by $$\phi_i$$. The magnetic flux through the area of the circular coil area is given by $$\phi_0$$. Which of the following option is correct?

NTA JEE Main 7th January 2020 Shift 1 - Question 14


A LCR circuit behaves like a clamped harmonic oscillator. Comparing it with a physical spring-mass damped oscillator having damping constant 'b', the correct equivalence would be:

NTA JEE Main 7th January 2020 Shift 1 - Question 15


If the magnetic field in a plane electromagnetic wave is given by $$\vec{B} = 3 \times 10^{-8} \sin(1.6 \times 10^3 x + 48 \times 10^{10} t)\hat{j}\,T$$, then what will be the expression for electric field?

NTA JEE Main 7th January 2020 Shift 1 - Question 16


If we need a magnification of 375 from a compound microscope of tube length 150mm and an objective of focal length 5mm, the focal length of the eye-piece, should be close to:

NTA JEE Main 7th January 2020 Shift 1 - Question 17


A polarizer - analyser set is adjusted such that the intensity of light coming out of the analyser is just 36% of the original intensity. Assuming that the polarizer - analyser set does not absorb any light, the angle by which the analyser needs to be rotated further, to reduce the output intensity to zero, is ($$\sin^{-1}\left(\frac{3}{5}\right) = 37^\circ$$)

NTA JEE Main 7th January 2020 Shift 1 - Question 18


Visible light of wavelength $$6000 \times 10^{-8}$$ cm falls normally on a single slit and produces a diffraction pattern. It is found that the second diffraction minimum is at 60$$^\circ$$ from the central maximum. If the first minimum is produced at $$\theta_1$$, then $$\theta_1$$ is close to

NTA JEE Main 7th January 2020 Shift 1 - Question 19


The time period of revolution of electron in its ground state orbit in a hydrogen atom is $$1.6 \times 10^{-16}$$ s. The frequency of revolution of the electron in its first excited state (in s$$^{-1}$$) is:

NTA JEE Main 7th January 2020 Shift 1 - Question 20


Which of the following gives a reversible operation?

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