[Download PDF] AP ICET 2013 Question Paper Paper with Solutions

Instructions

In the following questions pick the odd thing out :

AP ICET 2013 - Question 31

AP ICET 2013 - Question 32

AP ICET 2013 - Question 33

AP ICET 2013 - Question 34

AP ICET 2013 - Question 35

Instructions

Each of the questions follows definite pattern. Observe the same and fill in the blanks with suitable answers.

AP ICET 2013 - Question 36

$$\frac{1}{5}, \frac{5}{10}, \frac{10}{17}, \frac{17}{26}, ..........., \frac{37}{50}$$

AP ICET 2013 - Question 37

6, 12, 20, 30, ......, 56

Solution

The logic here is

12 - 6 = 6

20-12 = 8

30-20 = 10

The difference between the consecutive numbers is increasing by 2.

The next difference should be 12.

$$\therefore\ $$The missing number is 30+12 = 42

Hence, the correct answer is Option D

AP ICET 2013 - Question 38

$$\frac{1}{2}, \frac{8}{5}, \frac{27}{10}, ...... \frac{125}{26}, \frac{37}{50}$$

Solution

Numerator

1^3 =1

2^3 = 8

3^3 = 27

4^3 = 64

Denominator

5-2 = 3

10-5 = 5

next difference should be 7

Hence 10 + 7 = 17

AP ICET 2013 - Question 39

4, 1, 9, 3, 16, 6, 25, 10, 36, ............

AP ICET 2013 - Question 40

1, 4, 27, 256, .........

Solution

The logic here is

$$1^1=1$$

$$2^2=4$$

$$3^3=27$$

$$4^4=256$$

Similarly, the next number in the series = $$5^5=3125$$

Hence, the correct answer is Option D

CAT Content

AP ICET 2013 Question Paper

AP ICET 2013 Question Paper

AP ICET 2013 - Question 31

AP ICET 2013 - Question 32

AP ICET 2013 - Question 33

AP ICET 2013 - Question 34

AP ICET 2013 - Question 35

AP ICET 2013 - Question 36

AP ICET 2013 - Question 37

AP ICET 2013 - Question 38

AP ICET 2013 - Question 39

AP ICET 2013 - Question 40

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