Sign in
Please select an account to continue using cracku.in
↓ →
For,
$$3^{48} = x(mod 10)$$
We need to find remainder when $$3^{48\ }$$ is divided by 10.
3 has a cyclicity if 4. So as 48 is a multiple of 4, so last digit will be 1.
Hence remainder on division by 10 =1
1 Answer
Create a FREE account and get:
Book Free CAT Mentorship
Get personalized CAT strategy from a 99%iler
500+ students mentored
OTP Verification
Enter the 6-digit code sent to your phone
Booking Summary
Enter OTP
Didn't receive the OTP?
Educational materials for CAT preparation