Question 91

If the length and breadth of a rectangle are increased vy 20% each, then the area of the rectangle increases by x%, then x =

Solution

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Solution:

Let Original dimensions be l and b. 

Area = l x b

New Dimension be L and B

% Increase in l = 20

L = (100+20)% Of l = 1.2l

% Increase in b = 20

B = (100+20)% Of b = 1.2b

New Area = L x B = (1.2l)(1.2b) = 1.44 lb

% change increase in area = $$\frac{Difference In Area}{Old Area}$$ x 100

                                       = $$\frac{1.44lb-lb}{lb}$$ x 100 =44% Answer


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