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If the length and breadth of a rectangle are increased vy 20% each, then the area of the rectangle increases by x%, then x =
Solution:
Let Original dimensions be l and b.
Area = l x b
New Dimension be L and B
% Increase in l = 20
L = (100+20)% Of l = 1.2l
% Increase in b = 20
B = (100+20)% Of b = 1.2b
New Area = L x B = (1.2l)(1.2b) = 1.44 lb
% change increase in area = $$\frac{Difference In Area}{Old Area}$$ x 100
= $$\frac{1.44lb-lb}{lb}$$ x 100 =44% Answer
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