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A train travels a distance of 60 km in 40 minutes. If its velocity is decreased by 15 km/hour, then the time required by that train to travel the same distance, in minutes, is
Solution
Distance = 60km
Time =Β 40 minutes =Β $$\frac{40}{60}$$ hour =Β $$\frac{2}{3}$$ Hour
Speed = $$\frac{Distance}{Time}$$
SpeedΒ = $$\frac{60}{\frac{2}{3}}$$ =Β $$\frac{(60)(3)}{2}$$ = 90 kmph
Reduced speed = 90-15 = 75 kmph
Distance = 60 km
Speed = $$\frac{Distance}{Speed}$$
Time = $$\frac{60}{75}$$ =Β $$\frac{4}{5}$$ hr.=Β 48 minutes.
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