Question 97

Tap A can fill an empty tank in one hour, while a drain pipe B can empty that full tank in 6 hours. If both A and B are opened at the same instant, the total time taken to fill that empty tank,in hours, is

Solution

Solution:

Work done by A in 1 hour = 1 unit

Work done by B in 1 hour = - 1/6 unit

Total work done by A and B in 1 hr. = 1- $$\frac{1}{6}$$ = $$\frac{5}{6}$$

Time taken to fill the tank = $$\frac{1}{WorkIn1hour}$$ = 1/$$\frac{5}{6}$$ $$\frac{1}\frac{5}{6}$$

= $$\frac{6}{5}$$ Answer

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