The difference between the biggest and smallest fractions among $$\frac{1}{2}, \frac{5}{6}, \frac{7}{9}, \frac{4}{5}$$ is

Solution

$$\frac{1}{2}, \frac{5}{6}, \frac{7}{9}, \frac{4}{5}$$ 

LCM of denominators = LCM(2,6,9,5) = 90

Converting all the fractions to common base

$$\frac{1}{2}$$ = $$\frac{1 . 45}{2. 45}$$ = $$\frac{45}{90}$$

$$\frac{5}{6}$$ = $$\frac{5 . 15}{6 .15}$$ = $$\frac{75}{90}$$

$$\frac{7}{9}$$ = $$\frac{7 . 10}{9 . 10}$$ = $$\frac{70}{90}$$

$$\frac{4}{5}$$ = $$\frac{4 . 18}{5 . 18}$$ = $$\frac{72}{90}$$

As denominators are same, so fraction with biggest numerator is biggest and with smallest numarator is smallest.

Biggest fraction = $$\frac{75}{90}$$

Smallest fraction = $$\frac{45}{90}$$

Difference = $$\frac{75}{90}$$ - $$\frac{45}{90}$$ = $$\frac{30}{90}$$ = $$\frac{1}{3}$$ Answer