Question 121

Two poles of height 15 metres and 30 metres stand upright on a play ground .If the feet of the poles are 36 meters a part , then the distance between their tops are

Solution

A/q

AB = DE = 15m

So CD = CE - AB = 15m

Also given AE = 36m. It implies BD = 36.

Hence in right angle triangle BCD.

Base = 36m

Height = 15 m

So according to Pythagoras theorem Hypotenuse (or distance between their tops) will be 39m. Answer

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