Question 121
Two poles of height 15 metres and 30 metres stand upright on a play ground .If the feet of the poles are 36 meters a part , then the distance between their tops are
Solution
Solution
A/q
AB = DE = 15m
So CD = CE - AB = 15m
Also given AE = 36m. It implies BD = 36.
Hence in right angle triangle BCD.
Base = 36m
Height = 15 m
So according to Pythagoras theorem Hypotenuse (or distance between their tops) will be 39m. Answer
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