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If $$63 \times 65 \times 67 \times 69$$ is divided by 12 then the remainder obtained is
Solution:
Principle used to solve :Rem (A x B) = Rem. (A) x Rem. (B)
A/q
When divided by 12
Rem. (63 x 65 x 67 x 69) = Rem. (63) x Rem.(65) x Rem.(67) x Rem.(69)
The common multiple of 12 samller than all the above nos. is 60. So taking 60 as reference.
Rem. (63) x Rem.(65) x Rem.(67) x Rem.(69) = Rem. (3 x 5 x7 x9) = Rem.(945)
945 leaves a remainder of 9 when divided by 12, as 936 is the closest multiple of 12 before 945.
Hence Answer 9
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