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If the mid points of the sides AB and AC of a triangle ABC are (4, -2), (-8, 14) respectively, then the length of the side BC, in units, is
let the mid points of the slides AB and AC of the triangle is D(4,-2) and F(-8,14)Β
which is parallel to the BC and BC = 2DFΒ
then DF LengthΒ isΒ DF = (-8 +4) + (!4 + 2) = 20Β
then BC = 2* 20 = 40Β AnswerΒ
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