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If A is a 3 x 3, square matrix and if A Adj $$A = \begin{bmatrix}4 & 0 & 0\\0 & 4&0 \\ 0 & 0 & 4\end{bmatrix}$$, then det(2A) =
given thatΒ A Adj $$A = \begin{bmatrix}4 & 0 & 0\\0 & 4&0 \\ 0 & 0 & 4\end{bmatrix}$$
means that
A Adj $$A = \begin{bmatrix}4 & 0 & 0\\0 & 4&0 \\ 0 & 0 & 4\end{bmatrix}$$ = |A|I = 4 $$\begin{bmatrix}1 & 0 & 0\\0 & 1&0 \\ 0 & 0 & 1\end{bmatrix}$$
Β β£Aβ£=4
det (2Adj A)Β =Β β£Aβ£^(nβ1) , where n is number of rows in a matrix
Β Β Β Β Β Β Β Β Β Β Β =Β 2$$\times$$4^(3-1)
Β Β Β Β Β Β Β Β Β Β Β =Β 2$$\times$$ 16Β Β
Β Β Β Β Β Β Β Β Β Β Β = 32Β Β AnswerΒ
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