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Question 147

When two unbiased dice are thrown , the probability that they show up different numbers is

Solution

when the two unbiased dice are thrown the number of total cases are = 36

let the both the dice show the same number then cases are = (1,1), (2,2), (3,3),(4,4),(5,5) and (6,6) = 6

then the probility of getting different number = 1 - probility of getting same number on both dice

then the probility of getting different number= 1 - 6\36

then the probility of getting different number = 1-1\6

then the probility of getting different number = 5\6 Answer

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