Question 126

If x + y = 12 y + z = 20 and z + x = 18 then x - y + z =

Solution

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given that 

x + y = 12     equation 1 

y + z = 20     equation 2

z + x = 18      equation 3 

on adding equation  1 + 2 + 3 we get 

x + y + z = 25  equation 4   now perform operation eq4 - eq1, eq4 - eq2, and  eq4 - eq3 

we get 

x = 5 ,y = 7 and z = 13 then  put the value in eq following 

x - y + z = 5 - 7 + 13 = 11 Answer

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