SRCC GBO 2022

It is given in the question that Profit percent = $$\frac{Income - Expenditure}{Expenditure} \times 100$$.

That means profit is calculated as a percent of expenditure.

Income = Expenditure + $$\frac{profit percent * Expenditure}{100}$$

Let 'e' be the expenditure company A in 2019. 

The profit percentage of company A is 55, and B's is 40.

The income of company A in 2019 = Expenditure + $$\frac{profit percent * Expenditure}{100}$$ = e+$$\frac{55 * e}{100}$$=1.55e

The income of company B in 2019 = Expenditure + $$\frac{profit percent * Expenditure}{100}$$ = e+$$\frac{40 * e}{100}$$=1.4e

The total income of companies A and B in 2019 is 1.55e+1.4e = 2.95e.

Given that the total income of both companies was ₹354 crores.

So, 2.95e = 354

$$\Rightarrow$$ e = 120.

Then the total expenditure (in ₹ crores) of A and B in 2019 is 2e = 2*120=240

It is given in the question that Profit percent = $$\frac{Income - Expenditure}{Expenditure} \times 100$$.

That means profit is calculated as a percent of expenditure.

Income = Expenditure + $$\frac{profit percent * Expenditure}{100}$$

The question shows that the expenditure for company B in 2016 was ₹240 cr.

From the graph, the profit percent for company B in 2016 is 45.

Income for company B in 2016 = expenditure +  $$\frac{profit percent * Expenditure}{100}$$ = 240+ $$\frac{45 * 240}{100}$$ = ₹348 cr.

The income for company B in 2020 is also equal to ₹348 cr.

From the graph, the profit percent for company B in 2020 is 60.

Let's assume the expenditure of company B in 2020 is e. 

Income for company B in 2020 = expenditure + $$\frac{profit percent * Expenditure}$${100} 

348 = e+$$\frac{60 * e}{100}$$ = 1.6e

e = $$\frac{348}{1.6}$$ = 217.5

A total of 225 students passed from School Y in the year 2017. 
We are given that among these students, the boys and girls are in the ratio of 7:8
This would give us the girls passing from school Y in 2017 to be $$\frac{225}{15}\times\ 8=120$$, and the boys passing from school Y in 2017 to be $$\frac{225}{15}\times\ 7=105$$

Next, we are given the ratio of boys and girls that passed from school X in the year 2019 as 12:13
The total number of students that passed from X in 2019 is 280; this would give us the number of boys and girls passing in that year to be $$\frac{275}{25}\times\ 12=132$$ and $$\frac{275}{25}\times\ 13=143$$ respectively.

The total number of girls passing from X and Y would be: 120+143 = 263

We are given that in 2020, 80% of the students who appeared were girls, giving us this value to be $$\frac{80}{100}\times\ 400=320$$

We are asked how many percentages is 263 less than 320; this value would be $$\frac{320-263}{320}\times\ 100=17.81\%$$

Therefore, Option C is the correct answer.  

for this question, we only have to consider the data from School Z
We need to subtract the number of students who passed from the number of students who appeared for each year and see in which year is that value at the second lowest rank.

2016: 300-285 = 15

2017: 320-304 = 16

2018: 380-362 = 18

2019: 352-325 = 27

2020: 400-381 = 19

If we rank the years in the increasing order of their differences:
2016(15), 2017 (16), 2018 (18), 2020(19), 2019 (27)

We see that the year with the second-lowest difference is 2017

Therefore, Option A is the correct answer. 

For this question, we would have to find the total number of students that passed from school Y

The number of students that passed from school Y: 175+225+254+280+276 = 1210

The average number of students that passed from Y would be 1210/5 = 242

The average number of students that passed from all three schools combined in 2018 would be $$\frac{242+254+362}{3}=\frac{858}{3} = 286$$

Giving us the ratio to be $$242:286$$
$$11:13$$

Therefore, Option A is the correct answer. 

The total number of students that appeared from school X in 2016, 2017 and 2019 are 250+275+300 = 825

The number of students that passed from School Y in 2018 and 2020 is 254+276= 530

The difference between the two is 825-530 = 295

We need to find the percentage of this value compared to the total number of students who passed from school Y in 2018 and 2020, giving the answer to be $$\frac{295}{530}\times\ 100\approx\ 55.66\%$$

This is closest to option D, which shows a value of 55.7%

Therefore, Option D is the correct answer.