Question 99

If $$(21^{13} + 29^{13})$$ is divided by 25, then what is the remainder?

Solution

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To divide $$(21^{13} + 29^{13})$$ by 25, we shall divide 21 and 29 individually by 25. 

 By doing so, we get the remainder as $$(4^{13} + (-4)^{13})$$, which is 0. 

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