Solution
To divide $$(21^{13} + 29^{13})$$ by 25, we shall divide 21 and 29 individually by 25.
By doing so, we get the remainder as $$(4^{13} + (-4)^{13})$$, which is 0.
Sign in
Please select an account to continue using cracku.in
↓ →
To divide $$(21^{13} + 29^{13})$$ by 25, we shall divide 21 and 29 individually by 25.
By doing so, we get the remainder as $$(4^{13} + (-4)^{13})$$, which is 0.
