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Question 101
If the resulting numbers be the consecutive terms of Harmonic Progression, then what number should be added to the numbers 8, 10, 14?
Solution
Let the number subtracted be x. Hence, the terms are 8-x, 10-x, and 14-x.
10-x = $$\ \frac{\ 2\left(8-x\right)\left(14-x\right)}{8-x+14-x}$$
On cross multiplying, we get x as -2.
