NTA JEE Main 27th June 2022 Shift 2
For the following questions answer them individually
NTA JEE Main 27th June 2022 Shift 2 - Question 41
Given below are two statements: one is labelled as Assertion and the other is labelled as Reason.
Assertion: Flourine forms one oxoacid.
Reason: Flourine has smallest size amongst all halogens and is highly electronegative.
In the light of the above statements, choose the most appropriate answer from the Question: options given
below.
NTA JEE Main 27th June 2022 Shift 2 - Question 42
On the surface of polar stratospheric clouds, hydrolysis of chlorine nitrate gives A and B while its reaction with HCl produces B and C. A, B and C are, respectively
NTA JEE Main 27th June 2022 Shift 2 - Question 43
The 'f' orbitals are half and completely filled, respectively in lanthanide ions [Given : Atomic no. Eu, 63 : Sm, 62 : Tm, 69; Tb, 65; Yb, 70; Dy, 66]
NTA JEE Main 27th June 2022 Shift 2 - Question 44
Arrange the following coordination compounds in the increasing order of magnetic moments. (Atomic numbers: Mn = 25; Fe = 26)
A. $$[FeF_6]^{3-}$$
B. $$[Fe(CN)_6]^{3-}$$
C. $$[MnCl_6]^{3-}$$ (high spin)
D. $$[Mn(CN)_6]^{3-}$$
Choose the correct answer from the options given below
NTA JEE Main 27th June 2022 Shift 2 - Question 45
Match List-I with List-II
           List - I                               List - II
NTA JEE Main 27th June 2022 Shift 2 - Question 46
Decarboxylation of all six possible forms of diaminobenzoic acids $$C_6H_3(NH_2)_2COOH$$ yields three products A, B and C. Three acids give a product 'A', two acids give a product 'B' and one acid give a product 'C'. The melting point of product 'C' is
NTA JEE Main 27th June 2022 Shift 2 - Question 47
Which is true about Buna-N?
NTA JEE Main 27th June 2022 Shift 2 - Question 48
Match List - I with List - II.
     List - I               List - II
| (A) Antipyretic | (I) Reduces pain |
| (B) Analgesic | (II) Reduces stress |
| (C) Tranquilizer | (III) Reduces fever |
| (D) Antacid | (IV) Reduces acidity(stomach) |
Choose the correct answer from the options given below
NTA JEE Main 27th June 2022 Shift 2 - Question 49
Match List - I with List - II.
| List-I (Anion) | List-II (gas evolved on reaction with dil. $$H_2SO_4$$) |
|---|---|
| (A) $$CO_3^{2-}$$ | (I) Colourless gas which turns lead acetate paper black. |
| (B) $$S^{2-}$$ | (II) Colourless gas which turns acidified potassium dichromate solution green. |
| (C) $$SO_3^{2-}$$ | (III) Brown fumes which turns acidified KI solution containing starch blue. |
| (D) $$NO_2^-$$ | (IV) Colourless gas evolved with brisk effervescence, which turns lime water milky. |
Choose the correct answer from the options given below
NTA JEE Main 27th June 2022 Shift 2 - Question 50
Given below are two statements.
Statement I: Maltose has two $$\alpha - D$$ - glucose units linked at $$C_1$$ and $$C_4$$ and is a reducing sugar.
Statement II: Maltose has two monosaccharides: $$\alpha$$-D-glucose and $$\beta$$-D-glucose linked at $$C_1$$ and $$C_6$$ and it is a non-reducing sugar.
In the light of the above statements, choose the correct answer from the options Question: given below.
