pH value of $$0.001$$ M NaOH solution is ______

We need to find the pH of a 0.001 M NaOH solution. NaOH is a strong base that completely dissociates in water: $$NaOH \rightarrow Na^+ + OH^-$$.

Since NaOH dissociates completely: $$[OH^-] = 0.001 \text{ M} = 10^{-3} \text{ M}$$.

$$pOH = -\log[OH^-] = -\log(10^{-3}) = 3$$.

At 25°C, using the relation $$pH + pOH = 14$$: $$pH = 14 - pOH = 14 - 3 = 11$$.

The pH of the solution is 11.