CAT 1990 Question Paper

The difference in the excise duty as a percentage is least amongst AP and Maharashtra and it equals (60-52)/52 * 100 
This equals 8/52*100 = 200/13 = 15.38% which is approximately equal to 15%

In the question we are only provided with the data of five states. We don't know the excise duty rates for other states. Thus, the answer cannot be determined.

We know that the Excise duty is levied on the total value of liquor produced by the 5 distilleries. Since the excise duty remains constant, the excise duty will be in the same order as the order of the amount of the liquor produced by them.
Thus, the correct order is DCEBA.

Average simple annual growth of the distilleries are-

A->$$\frac{12.89-6.41}{2\times6.41}\times100=50.54$$%
B->$$\frac{12.07-3.15}{2\times3.15}\times100=141.58$$%
C->$$\frac{11.92-1.64}{2\times1.64}\times100=313.41$$%
D->$$\frac{5.79-1.05}{2\times1.05}\times100=225.71$$%

E->$$\frac{4.21-2.45}{2\times2.45}\times100=35.91$$%

We can see that the highest growth rate was in C and lowest in E.
So, if E would have grown by 313.41% in 2 years, its supply would have been-

$$\frac{2.45\times 313.41\times 2}{100}=15.11$$ lts

Assume the first statement is true. So, Saira has the ball. The other two statements are false. But if Saira has the ball, the statement that Mumtaz does not have the ball is true. But that statement should be false. Therefore, the first statement cannot be true.

Assume the second statement is true. So, Mumtaz does not have the ball. Also, since the other two statements are false, Saira also does not have the ball. So, Zeenat has the ball. But the third statement "Zeenat does not have a pen" becomes true in this case, which is incorrect. So, the second statement also cannot be true.

The only possibility is the statement has to be true. So, the second statement is false => Mumtaz has the ball.

According to given question Jerome + Tommy = Albert + David  eq.(1)    ;    Jerome < Tommy  eq. (3)
                                                   Albert + Tommy < David + jerome eq. (2)
Now adding above two equations we will get
2David  > 2Tommy
or David > Tommy
or Tommy > Jerome > Albert ( from eq.(3) )
Now David should earn most pocket money as to hold equation (2) to be true.
Hence David > Tommy > Jerome > Albert.

Given informations are as follows:

Akhila got 13 marks in coherence and divya got 10 marks in Machinary

Divya's marks = Ela's Marks (Hence they both are not winners as winner is only one)

Bhanu's marks < Akhila's marks ( Hence bhanu is also not a winner)

So winner will be either Akhila or Charulata

As Akhila got 13 marks in coherence so she must have 20 marks in some head as highest marks are 90

That's why winner will be Charulata.

Average of numbers 100.5 , 67, 141, 143.9 and 65 will be

$$100 + \frac{41+0.5+43.9-33-35}{5} = 103.48 $$

Base value must be taken as 100 => 1985 is 100

1984 => $$\frac{100.5}{67}*100$$ = 150

1986 => $$\frac{141}{67}*100$$ = 211

Only option A has the same values => Option A is the answer

Decline occur in years 1985 and 1988 respectively.
In year 1985, decline was nearly 33%
Whether in year 1988 decline was nearly 54%
Hence answer will be B.