[Download PDF] MAT 2009 Question Paper Paper with Solutions

Instructions

Study the following graphs to answer these questions.

MAT 2009 - Question 121

During the years 1997-99, the magazine that has shown maximum percentage growth in circulation has been

Video Solution

Solution

Clearly, growth in circulation of magazines in DSJ is from 18000 to 49000, which is more than double, and for other magazines, it is less than double, hence percentage growth is maximum in DSJ.

=> Ans - (A)

MAT 2009 - Question 122

In 1999, if Fortune India were to charge the same rate to its advertisers as Dalal Street Journal was charging a year ago, their cost of advertisement per thousand copies in fortune India would

Video Solution

Solution

Advertisement tariff for FI in 1999 = Rs. 28000

Advertisement tariff for DSJ in 1998 = Rs. 14000

=> Decrease in their cost = $$\frac{28000-14000}{28000}\times100=50\%$$

=> Ans - (B)

MAT 2009 - Question 123

In 1998, the advertisement cost for colour page per thousand copies was the lowest for

Video Solution

Solution

Advertisement cost for colour page per thousand copies in 1998 for :

DSJ = $$\frac{14,000\times1000}{40,000}=Rs.$$ $$350$$ [MIN]

BI = $$\frac{30,000\times1000}{50,000}=Rs.$$ $$600$$

BW = $$\frac{20,000\times1000}{30,000}=Rs.$$ $$666$$

FI = $$\frac{17,000\times1000}{27,000}=Rs.$$ $$630$$

=> Ans - (A)

MAT 2009 - Question 124

The advertisement cost of colour page per thousand copies for Business World has, from 1997 to 1998

Video Solution

Solution

Advertising Cost per 1000 copies of Business World in 1997 = $$\frac{5000\times1000}{25000}=Rs.$$ $$200$$

Advertising Cost per 1000 copies of Business World in 1998 = $$\frac{20,000\times1000}{30000}=Rs.$$ $$666$$

=> The cost increased by = $$666-200=Rs.$$ $$466$$

=> Ans - (C)

Instructions

Each question consists of two quantities, one in Column A and one in Column B. Compare the two quantities and choose answer option as

MAT 2009 - Question 125

Video Solution

Solution

Column A : Number of posts needed = $$\frac{144}{12}+1=13$$ posts

Column B : $$12$$ posts

Quantity in column A is bigger.

=> Ans - (B)

MAT 2009 - Question 126

Video Solution

Solution

Column A : Time elapsed from 2:55 pm to 3:15 pm = 20 minutes

Column B : $$\frac{1}{3}$$ hours = 20 minutes

Both quantities are equal.

=> Ans - (C)

MAT 2009 - Question 127

Column A Column B

$$\frac{1}{3}$$ of 8 $$66\frac{2}{3}\%$$ of 4

Video Solution

Solution

Column A : $$\frac{1}{3}\times8=\frac{8}{3}$$

Column B : $$66\frac{2}{3}\%$$ of 4

= $$\frac{200}{3}\times\frac{1}{100}\times4=\frac{8}{3}$$

Both quantities are equal.

=> Ans - (C)

MAT 2009 - Question 128

Column A Column B

The average of $$\sqrt{0.49}, \frac{3}{4}$$ and 0.8 75%

Video Solution

Solution

Column A : Average of 0.7, 0.75, 0.8

= $$\frac{0.7+0.75+0.8}{3}=0.75=75\%$$

Column B : $$75\%$$

Both quantities are equal.

=> Ans - (C)

Instructions

Read the following information to mean these answers.

Six books are kept one on top of the other. The History book is Just above Accountancy. The Maths books is between Punjabi and Urdu. English is between History and Punjabi.

MAT 2009 - Question 129

Which book is between the Maths and English books?

Video Solution

MAT 2009 - Question 130

Which book is at the bottom?

Video Solution

CAT Content

MAT 2009 Question Paper

MAT 2009 Question Paper

MAT 2009 - Question 121

MAT 2009 - Question 122

MAT 2009 - Question 123

MAT 2009 - Question 124

MAT 2009 - Question 125

MAT 2009 - Question 126

MAT 2009 - Question 127

MAT 2009 - Question 128

MAT 2009 - Question 129

MAT 2009 - Question 130

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