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Question 96
If the total power generated in thermal units be 40% of the installed capacity, in hydel units be 50% of the installed capacity and in nuclear be 90% of the installed capacity, the total power generation in 1998 would be
Solution
The total power generation in 1998
= $$(\frac{40}{100}\times15200)+(\frac{50}{100}\times10200)+(\frac{90}{100}\times800)$$
= $$6080+5100+720=11900$$ MW
=> Ans - (B)
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