Question 65

A portion of a 30 m long tree is broken by a tornado and the top strikes the ground making an angle of $$30^\circ$$ with the ground level. The height of the point where the tree is broken is equal to :

Solution

The height of tree (before it broke) = AB + AC = 30 m. Let AB = $$h$$ m

In right $$\triangle$$ ABC,

=> $$sin(30^\circ)=\frac{AB}{AC}$$

=> $$\frac{1}{2}=\frac{h}{30-h}$$

=> $$30-h=2h$$

=> $$h=\frac{30}{3}=10$$

$$\therefore$$ Height where the tree broke = 10 m

=> Ans - (A)

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