An office has as many four-legged chairs and as many four-legged tables as workers, and as many three-legged stools as four-legged almirahs. If the number of stools be one more than the number of workers and the total number of legs be 585, the number of workers in the office are?
Number of workers = Number of 4 legged chairs = Number of 4 legged tables = $$x$$
Number of 3 legged stools = Number of 4 legged almirahs = $$y$$
According to ques, => $$y=x+1$$ ---------------(i)
Total legs = $$(2x+4x+4x)+(3y+4y)=585$$
=> $$10x+7y=585$$
Substituting value from equation (i), => $$10x+7(x+1)=585$$
=> $$17x=585-7=578$$
=> $$x=\frac{578}{17}=34$$
=> Ans - (B)
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