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Question 80

A mixture (40 L) contains coniac and water in the ratio $$3 : 1$$. To make the ratio $$5 : 2$$. How much additional amount of water is required?

Solution

Quantity of coniac in the mixture = 30 $$l$$ and quantity of water = 10 $$l$$

Let $$x$$ $$l$$ of water is added.

=> $$\frac{30}{10+x}=\frac{5}{2}$$

=> $$12=10+x$$

=> $$x=2$$

$$\therefore$$ 2 L of additional water is required.

=> Ans - (D)

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