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A mixture (40 L) contains coniac and water in the ratio $$3 : 1$$. To make the ratio $$5 : 2$$. How much additional amount of water is required?
Quantity of coniac in the mixture = 30 $$l$$ and quantity of water = 10 $$l$$
Let $$x$$ $$l$$ of water is added.
=> $$\frac{30}{10+x}=\frac{5}{2}$$
=> $$12=10+x$$
=> $$x=2$$
$$\therefore$$ 2 L of additional water is required.
=> Ans - (D)
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