sbi-associate-po-2007

Distance = Speed $$\times$$ Time

Initial speed = 70 kmph

In first 2 hours, motor covers a distance = $$70 \times 2 = 140~km$$

Speed after 2 hours = 70 + 10 = 80 kmph

In the next 2 hours, it covers a distance = $$80 \times 2 = 160~km$$

Distance covered = 300 km

Now, the speed is 90 kmph

Remaining 45 km is covered in $$\frac{45}{90}$$ = 0.5 hr

Total time taken to cover 345 km = 2 + 2 + 0.5 = 4.5 hr

here the cost of boundary making = 10 per sqmt

Total area to be boundaried = 2 L + 2B + (1×4)...(1)

It is given that perimeter of rectangle is 340 m

So 2(L + B ) = 340....(2)

From equation 1 and 2

Total area to be boundaried = 344 sq mtr

Cost of boundaring 344 sq mtr area = 344 × 10 = Rs 3440

The number of ways of selecting 4 men from 7 men is $$^7C_4 = 35$$
The number of ways of selecting 4 women from 8 women is $$^8C_4 = 70$$

Hence, the total number of ways is $$70 \times 35 = 2450$$

As we don't know 2 variables, the principal and rate of interest, we cannot determine the change in interest earned.

Let the original number of seats in Maths, Physics and Biology be 5X, 7X and 8X.
So, the respective increases in seats equals 5X*0.4, 7X*0.5 and 8X*0.75
That is 2X, 3.5X and 6X

Hence, the final number of seats equals 5X+2X,7X+3.5X and 8X+6X = 7X,10.5X,14X
So, the final ratio is 7:10.5:14 = 2:3:4

Profit = Revenue - Expenditure

(d) is not correct as it doesn't take into account profit's dependence on expenditure

(e) is not correct as expenditure and revenue are independent.

(c) is incorrect as profit in 2006 = profit in 2007

(a) is incorrect as revenue and expenditure in 2007 were not the same as shown in the graph.

So, (b) is the correct answer.

A- 28*2 + 13*3 = 95

B- 20*2 + 28*2 = 96

C- 13*1 + 28*3 = 97 (MAX)

D- 13*3 + 28*1 + 20*1 = 87

E- 28*1.5 + 20*1.5 + 13*1.5 = 91.5

$$A = \frac{x}{100} \times y = \frac{xy}{100}$$
$$B = \frac{y}{100} \times x = \frac{xy}{100}$$
A = B

number of male literate = (35/100) * 2,50,000 = 87,500

number of female literate = (8/100) * 2,50,000 = 20,000

difference = 87,500-20,000 = 67,500

(Method II)

% of male literate = 35%

% of female literate = 8%

difference = 35- 8 =27%

ans = (27/100) * 2,50,000 = 67,500

Case (i) When a > 1
Let a = 2
x = 2, y = 1
$$\therefore$$ x > y

Case (ii) When a < 1
Let a = 0
x = 0, y = -1
$$\therefore$$ x > y