How many such 5s are there in the following sequence that the sum of the two immediately following digits is greater than the sum of the two immediately preceding digits ?
3 7 6 5 8 3 2 4 5 5 4 8 7 9 1 5 3 4 8 7 5 9 8 7 6 4
Solution
Given sequence 3 7 6 5 8 3 2 4 5 5 4 8 7 9 1 5 3 4 8 7 5 9 8 7 6 4
5's for which the sum of following two digits is greater than the sum of preceding two digits are highlighted below
3 7 6 5 8 3 2 4 5 5 4 8 7 9 1 5 3 4 8 7 5 9 8 7 6 4, Thus there are 3 such 5's so option 3
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