Instructions

In each of the following question two equations are given you have to solve them and
Give answer (a)if pGive answer (b)if p>q
Give answer (c)if $$p\leq$$q
Give answer(d)if $$p\geq$$q
Give answer (e)if p=q

Question 93

I.$$p^{2}+12p+35=0$$
II.$$2q^{2}+22q+56=0$$

Solution

$$p^2+12p+35 = 0$$
$$(p+5)(p+7) = 0$$
$$p = -5, -7$$

$$2q^2+22q+56 = 0$$
$$q^2+11q+28 = 0$$
$$(q+4)(q+7) = 0$$
$$q = -4, -7$$

As we can see $$p$$ can be greater than, less than or equal to $$q$$. No relationship can be established between $$p$$ and $$q$$ and hence, option E is the right answer.

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I.$$p^{2}+12p+35=0$$ II.$$2q^{2}+22q+56=0$$

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I.$$p^{2}+12p+35=0$$
II.$$2q^{2}+22q+56=0$$