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Instructions
In each of the following question two equations are given you have to solve them and
Give answer (a)if p
Give answer (c)if $$p\leq$$q
Give answer(d)if $$p\geq$$q
Give answer (e)if p=q
Solution
$$12p^2-7p+1 = 0$$
$$(4p-1)(3p-1) = 0$$
$$p = \frac{1}{3}, \frac{1}{4}$$
$$6q^2-7q+2 = 0$$
$$(2q-1)(3q-2) = 0$$
$$q = \frac{1}{2}, \frac{2}{3}$$
$$\therefore p < q$$
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