Instructions

In each of the following question two equations are given you have to solve them and
Give answer (a)if pGive answer (b)if p>q
Give answer (c)if $$p\leq$$q
Give answer(d)if $$p\geq$$q
Give answer (e)if p=q

Question 91

I.$$p^{2}-7p=-12$$
II.$$q^{2}-3q+2=0$$

Solution

$$p^2-7p+12 = 0$$
$$(p-3)(p-4) = 0$$
$$p = 3, 4$$

$$q^2-3q+2 = 0$$
$$(q-1)(q-2) = 0$$
$$q = 1, 2$$

$$\therefore p > q$$

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I.$$p^{2}-7p=-12$$ II.$$q^{2}-3q+2=0$$

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I.$$p^{2}-7p=-12$$
II.$$q^{2}-3q+2=0$$