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Tangent in Terms of Eccentric Angle
At:
$$P(a\cos\theta,b\sin\theta)$$
the tangent is:
$$\frac{x\cos\theta}{a}+\frac{y\sin\theta}{b}=1$$
Usage
- Used to obtain the tangent directly from the eccentric angle.
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Tangent in Terms of Eccentric Angle
At:
$$P(a\cos\theta,b\sin\theta)$$
the tangent is:
$$\frac{x\cos\theta}{a}+\frac{y\sin\theta}{b}=1$$
Usage
- Used to obtain the tangent directly from the eccentric angle.
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