Area of Parallelogram Formed by Conjugate Diameters
If the semi-diameters are $$p$$ and $$q$$ and the angle between them is $$\phi$$, then the area of the parallelogram formed by the conjugate diameters is:
$$A=4pq\sin\phi$$
For an ellipse, this area is constant:
$$A=4ab$$
Usage
- Used in area problems involving conjugate diameters.
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