Polar of a Point
For the ellipse:
$$\frac{x^2}{a^2}+\frac{y^2}{b^2}=1$$
the polar of the point:
$$P(x_1,y_1)$$
is:
$$\frac{xx_1}{a^2}+\frac{yy_1}{b^2}=1$$
Usage
- Used to find the polar of an external, internal or arbitrary point with respect to the ellipse.