NTA JEE Main 15th April 2023 Shift 1

The electric field due to a short electric dipole at a large distance $$(r)$$ from center of dipole on the equatorial plane varies with distance as :

For designing a voltmeter of range 50 V and an ammeter of range 10 mA using a galvanometer which has a coil of resistance 54 $$\Omega$$ showing a full scale deflection for 1 mA as in figure.

(A) for voltmeter $$R \approx 50$$ k$$\Omega$$
(B) for ammeter $$r \approx 0.2 \ \Omega$$
(C) for ammeter $$r \approx 6 \ \Omega$$
(D) for voltmeter $$R \approx 5$$ k$$\Omega$$
(E) for voltmeter $$R \approx 500 \ \Omega$$
Choose the correct answer from the options given below:

Given below are two statements:
Statement I : The equivalent resistance of resistors in a series combination is smaller than least resistance used in the combination.
Statement II : The resistivity of the material is independent of temperature. In the light of the above statements, choose the correct answer from the options given below:

In the given circuit, the current $$I$$ through the battery will be

A 12 V battery connected to a coil of resistance 6 $$\Omega$$ through a switch, drives a constant current in the circuit. The switch is opened in 1 ms. The emf induced across the coil is 20 V. The inductance of the coil is :

Match List-I with List II of Electromagnetic waves with corresponding wavelength range:

A single slit of width $$a$$ is illuminated by a monochromatic light of wavelength $$600$$ nm. The value of $$a$$ for which first minimum appears at $$\theta = 30°$$ on the screen will be :

The de Broglie wavelength of an electron having kinetic energy $$E$$ is $$\lambda$$. If the kinetic energy of electron becomes $$\frac{E}{4}$$, then its de-Broglie wavelength will be:

The half-life of a radioactive nucleus is 5 years. The fraction of the original sample that would decay in 15 years is :

The height of transmitting antenna is 180 m and the height of the receiving antenna is 245 m. The maximum distance between them for satisfactory communication in line of sight will be: (given $$R = 6400$$ km)