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Question 3

The position of a particle related to time is given by $$x = (5t^2 - 4t + 5)$$ m. The magnitude of velocity of the particle at $$t = 2$$ s will be :

$$x = 5t^2 - 4t + 5$$

Velocity: $$v = \frac{dx}{dt} = 10t - 4$$

At $$t = 2$$ s: $$v = 10(2) - 4 = 20 - 4 = 16$$ m/s

The magnitude of velocity is $$\mathbf{16}$$ m/s.

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