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Question 14

In the given circuit, the current $$I$$ through the battery will be

Solution

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$$V_{\text{right}} > V_{\text{left}} \implies D_1, D_3 \text{ forward-biased, } D_2 \text{ reverse-biased}$$

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$$I = \frac{10}{20/3}$$

$$I = 1.5 \text{ A}$$

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