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The total change in the oxidation state of manganese involved in the reaction of KMnO$$_4$$ and potassium iodide in the acidic medium is _____.
Correct Answer: 5
In acidic medium, KMnO₄ reacts with KI:
$$2KMnO_4 + 10KI + 8H_2SO_4 \to 2MnSO_4 + 5I_2 + 6K_2SO_4 + 8H_2O$$
Manganese changes from +7 (in KMnO₄) to +2 (in MnSO₄).
Total change in oxidation state = 7 - 2 = 5.
This matches the answer key value of $$\mathbf{5}$$.
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