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Question 8

A thermodynamic system is taken through cyclic process. The total work done in the process is :

Work Done = $$\text{Area of } \triangle CDE = \frac{1}{2} \times \text{Base} \times \text{Height}$$

$$W = \frac{1}{2} \times 2 \text{ m}^3 \times 300 \text{ Pa}$$

$$W = 300 \text{ J}$$

Since the cycle $$C \to D \to E \to C$$ is clockwise, the net work done is positive. 

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