Which of the following expressions is correct in case of a CsCl unit cell (edge length 'a')?

In a CsCl unit cell, Cs⁺ occupies the body center and Cl⁻ occupies the corners (or vice versa). The ions touch along the body diagonal.

Body diagonal of a cube with edge length $$a$$: $$d = \sqrt{3}a$$

The body diagonal connects opposite corners passing through the center. Along this diagonal:

$$2(r_{Cs^+} + r_{Cl^-}) = \sqrt{3}a$$

$$r_{Cs^+} + r_{Cl^-} = \frac{\sqrt{3}}{2}a$$

This matches option 2.

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