JEE WhatsApp Group
Sign in
Please select an account to continue using cracku.in
↓ →
JEE WhatsApp Group
Join Our JEE Preparation Group
Prep with like-minded aspirants; Get access to free daily tests and study material.
$$20$$ mL of $$0.5$$ M NaCl is required to coagulate $$200$$ mL of As$$_2$$S$$_3$$ solution in 2 hours. The coagulating value of NaCl is _____.
Correct Answer: 50
Coagulating value is defined as the millimoles of electrolyte required to cause coagulation of 1 L of sol.
Millimoles of NaCl used = 20 × 0.5 = 10 mmol
Volume of sol = 200 mL = 0.2 L
Coagulating value = $$\frac{10}{0.2} = 50$$ mmol/L
The coagulating value is $$\mathbf{50}$$.
Click on the Email ☝️ to Watch the Video Solution
Create a FREE account and get:
Educational materials for JEE preparation
Ask our AI anything
AI can make mistakes. Please verify important information.
AI can make mistakes. Please verify important information.
