JEE Basic Concepts in Chemistry PYQ
The chapter “Some Basic Concepts of Chemistry” is one of the most important chapters for JEE preparation. It includes topics such as the mole concept, molar mass, stoichiometry, empirical formula, molecular formula, concentration terms, and percentage composition.
Solving JEE Basic Concepts in Chemistry PYQ helps you understand how questions are asked in the exam. It also improves your calculation speed and helps you find the topics that need more revision.
This chapter may look simple, but students often lose marks because of small mistakes. These mistakes usually happen while converting units, calculating moles, or using the wrong formula. Regular practice can help you avoid such errors.
On this page, you can revise important formulas, download the PYQ PDF, check common mistakes, and practise questions in a test format.
JEE Basic Concepts in Chemistry PYQ
Previous-year questions are very useful for JEE preparation. They show you the type of questions asked in the exam and the level of difficulty you can expect.
While solving JEE Basic Concepts in Chemistry Questions, do not try to memorise the answers. First, understand what the question is asking. Write down the given values, check the units, and then choose the correct formula.
For questions based on chemical reactions, always balance the equation before starting the calculation. The coefficients in a balanced equation give the correct mole ratio between reactants and products.
In limiting reagent questions, do not simply choose the reactant with the smaller mass. Convert the mass of each reactant into moles and compare the mole ratio with the balanced equation.
A good way to practise is to solve one JEE Main PYQ set within a fixed time. After finishing the set, check your answers and note your mistakes. Try to understand whether the mistake happened because of a weak concept, a wrong formula, or a calculation error.
You can revise these mistakes before attempting your next JEE Mock Test. This simple habit can improve both speed and accuracy.
JEE Basic Concepts in Chemistry PYQs PDF
You can use the JEE Basic Concepts in Chemistry PYQs PDF given below for chapter-wise practice.
First, try to solve all the questions without checking the answers. You can also set a timer to create an exam-like environment.
After completing the PDF, divide the questions into three groups:
- Easy questions
- Questions that took more time
- Questions you could not solve
Revise the concepts used in the difficult questions and attempt them again after a few days.
You can also print the PDF and use it as a practice worksheet. While solving JEE Main questions, write all the calculation steps clearly. This will help you find mistakes during revision.
Do not only read the solutions. Try to solve each question on your own before checking the correct method.
Important Formulas for JEE Basic Concepts in Chemistry PYQs
The following formulas are commonly used in this chapter. You can add them to your JEE Mains Formula Sheet for quick revision.
| Concept | Formula | Simple Explanation |
|---|---|---|
| Number of moles | n = Given mass ÷ Molar mass | Use this formula when mass is given. |
| Number of particles | N = n × Nₐ | Nₐ is 6.022 × 10²³ particles per mole. |
| Molarity | M = Moles of solute ÷ Volume of solution in litres | Convert millilitres into litres before using the formula. |
| Molality | m = Moles of solute ÷ Mass of solvent in kg | Use the mass of the solvent, not the solution. |
| Mole fraction | X = Moles of one component ÷ Total moles | The sum of all mole fractions is equal to 1. |
| Mass percentage | Mass of component ÷ Total mass × 100 | Keep both masses in the same unit. |
| Percentage composition | Mass of element ÷ Molar mass of compound × 100 | Used to find the percentage of an element in a compound. |
| Molecular formula | Empirical formula × n | n = Molar mass ÷ Empirical formula mass. |
| Ideal gas equation | PV = nRT | Use the correct value of R according to the units. |
| Percentage yield | Actual yield ÷ Theoretical yield × 100 | Theoretical yield depends on the limiting reagent. |
Do not learn these formulas without practising questions. You should also understand when and where each formula is used.
For example, molarity uses the volume of the solution, while molality uses the mass of the solvent.
Common Mistakes to Avoid in JEE Basic Concepts in Chemistry PYQs
Many students make mistakes because they start calculations without balancing the chemical equation. Always balance the equation before using mole ratios.
Another common mistake is mixing up molarity and molality. Molarity depends on the volume of the solution in litres. Molality depends on the mass of the solvent in kilograms.
Students also make errors while finding the limiting reagent. The reactant with the lower mass is not always the limiting reagent. You must first convert both reactants into moles.
Unit conversion is another important area. Remember to:
- Convert millilitres into litres for molarity.
- Convert grams into kilograms for molality.
- Use the correct temperature and pressure units in gas-law questions.
- Keep all mass values in the same unit.
Avoid rounding numbers too early. Keep one or two extra decimal places during the calculation and round the final answer at the end.
After solving a JEE Main PYQ, also check why the other options are wrong. This will help you understand common traps used in the exam.
List of JEE Electrochemistry PYQs
Use the section below as a practice test. Each question can have four options so that students can solve it like a real exam.
Question 1
The processes of calcination and roasting in metallurgical industries, respectively, can lead to:
correct answer:- 2
Question 2
A transition metal $$M$$ forms a volatile chloride which has a vapour density of 94.8. If it contains 74.75% of chlorine the formula of the metal chloride will be
correct answer:- 3
Question 3
'$$a$$' and '$$b$$' are van der Waals' constants for gases. Chlorine is more easily liquefied than ethane because:
correct answer:- 3
Question 4
The hardness of a water sample containing $$10^{-3}$$ M $$MgSO_4$$ expressed as $$CaCO_3$$ equivalents (in ppm) is ___________.
(molar mass of $$MgSO_4$$ is 120.37 g/mol)
correct answer:- 100
Question 5
A sample of CaCO$$_3$$ and MgCO$$_3$$ weighed 2.21 g is ignited to constant weight of 1.152 g. The composition of the mixture is: (Given molar mass in g mol$$^{-1}$$, CaCO$$_3$$: 100, MgCO$$_3$$: 84)
correct answer:- 1
Question 6
Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A) : Heavy water is used for the study of reaction mechanism.
Reason (R): The rate of reaction for the cleavage of O-H bond is slower than that of O-D bond.
Choose the most appropriate answer from the options given below:
correct answer:- 2
Question 7
Which of the following is a set of greenhouse gases?
correct answer:- 3
Question 8
An aqueous solution of a commercially available acid has a density of $$1.25\text{ g mL}^{-1}$$ and is labeled as $$36.5\%$$ by mass of $$\text{HCl}$$. Calculate the
molality (m)
and
molarity (M)
of this $$\text{HCl}$$ solution respectively.
(Take molar mass of $$\text{HCl} = 36.5\text{ g mol}^{-1})$$
correct answer:- 2
Question 9
A metal M crystallizes into two lattices :- face centred cubic (fcc) and body centred cubic (bcc) with unit cell edge length of $$2.0$$ and $$2.5$$ Å respectively. The ratio of densities of lattices fcc to bcc for the metal M is ______ (Nearest integer)
correct answer:- 4
Question 10
The primary pollutant that leads to photochemical smog is:
correct answer:- 1
Question 11
Excess of NaOH (aq) was added to 100 mL of FeCl$$_3$$ (aq) resulting into 2.14 g of Fe(OH)$$_3$$. The molarity of FeCl$$_3$$(aq) is: (Given the molar mass of Fe = 56 g mol$$^{-1}$$ and molar mass of Cl = 35.5 g mol$$^{-1}$$)
correct answer:- 2
Question 12
Identify the pollutant gases largely responsible for the discoloured and lustreless nature of marble of the Taj Mahal.
correct answer:- 3
Question 13
At 300 K, the density of a certain gaseous molecule at 2 bar is double to that of dinitrogen (N$$_2$$) at 4 bar. The molar mass of the gaseous molecule is
correct answer:- 2
Question 14
The molecular formula of a commercial resin used for exchanging ions in water softening is $$C_8H_7SO_3Na$$ (molecular weight = 206). What would be the maximum uptake of $$Ca^{2+}$$ ions by the resin if expressed in mol per gm?
correct answer:- 1
Question 15
The higher concentration of which gas in air can cause stiffness of flower buds?
correct answer:- 3
Question 16
Taj Mahal is being slowly disfigured and discoloured. This is primarily due to
correct answer:- 2
Question 17
Among $$10^{-9}$$ g (each) of the following elements, which one will have the highest number of atoms?
Element : Pb, Po, Pr and Pt
correct answer:- 2
Question 18
The molecule that has minimum or no role in the formation of photochemical smog, is:
correct answer:- 1
Question 19
Match Column I with Column II
Column I Column II
A. Soda ash I. CaSO$$_4$$
B. Chlorophyll II. CaOH$$_2$$
C. Used in Whitewashing III. Na$$_2$$CO$$_3$$
D. Dentistry, ornamental work IV. Mg$$^{2+}$$ ions
correct answer:- 1
Question 20
0.27 g of a long chain fatty acid was dissolved in 100 cm$$^3$$ of hexane. 10 mL of this solution was added dropwise to the surface of water in a round watch glass. Hexane evaporates and a monolayer is formed. The distance from edge to centre of the watch glass is 10 cm. What is the height of the monolayer?
[Density of fatty acid = 0.9 g cm$$^{-3}$$; $$\pi = 3$$]
correct answer:- 2
Question 21
Which is wrong with respect to our responsibility as a human being to protect our environment?
correct answer:- 1
Question 22
Biochemical Oxygen Demand (BOD) is the amount of oxygen required (in ppm):
correct answer:- 2
Question 23
The elemental composition of a compound is $$54.2\%C,\ 9.2\%H$$ and $$36.6\%O.$$ If the molar mass of the compound is $$132\ \text{g mol}^{-1},$$ the molecular formula of the compound is: [Given: Relative atomic masses C:H:O = 12:1:16]
correct answer:- 4
Question 24
For per gram of reactant, the maximum quantity of N$$_2$$ gas is produced in which of the following thermal decomposition reactions? (Given: Atomic wt. : Cr = 52u, Ba = 137u)
correct answer:- 3
Question 25
A sample of NaClO$$_3$$ is converted by heat to NaCl with a loss of 0.16 g of oxygen. The residue is dissolved in water and precipitated as AgCl. The mass of AgCl (in g) obtained will be: (Given: Molar mass of AgCl = 143.5 g mol$$^{-1}$$)
correct answer:- 4
Question 26
NaClO$$_3$$ is used, even in spacecrafts, to produce O$$_2$$. The daily consumption of pure O$$_2$$ by a person in 492 L at 1 atm, 300K. How much amount of NaClO$$_3$$, in grams, is required to produce O$$_2$$ for the daily consumption of a person at 1 atm, 300K?
NaClO$$_3$$(s) + Fe(s) $$\rightarrow$$ O$$_2$$(g) + NaCl(s) + FeO(s)
R = 0.082 L atm mol$$^{-1}$$ K$$^{-1}$$
correct answer:- 2130
Question 27
The correct statements among (a) to (d) regarding $$H_2$$ as a fuel are: (i) It produces less pollutants than petrol. (ii) A cylinder of compressed dihydrogen weighs ~ 30 times more than a petrol tank producing the same amount of energy. (iii) Dihydrogen is stored in tanks of metal alloys like $$NaNi_5$$. (iv) On combustion, values of energy released per gram of liquid dihydrogen and LPG are 50 and 142 kJ, respectively.
correct answer:- 4
Question 28
At 300 K and 1 atmospheric pressure, 10 mL of a hydrocarbon required 55 mL of O$$_2$$ for complete combustion, and 40 mL of CO$$_2$$ is formed. The formula of the hydrocarbon is:
correct answer:- 3
Question 29
Water samples with BOD values of 4 ppm and 18 ppm, respectively, are:
correct answer:- 4
Question 30
A 100 mL solution was made by adding 1.43 g of $$Na_2CO_3 \cdot xH_2O$$. The normality of the solution is 0.1 N. The value of x is __________ (The atomic mass of Na is 23 g/mol)
correct answer:- 10
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