MAT 2001 Question Paper

The number of children who are working is to be determined from the 4th column from the left. 

Rural males (5-9) working in millions = (1.3/100)*39.7 = 0.5161 million
Rural females (5-9) working in millions = (3/100)*35.7 = 1.071 million  
And so on, doing approx calculations and adding up all results, the sum comes close to approx 18 million

Number of children not in school and not working in all categories (in millions) :

= $$(\frac{31.5}{100}\times13.02)+(\frac{40.8}{100}\times15.63)+(\frac{15.2}{100}\times1.79)+(\frac{18.6}{100}\times2.02)+(\frac{10.6}{100}\times8.44)+(\frac{14}{100}\times13.42)+$$

$$(\frac{5.8}{100}\times1.5)+(\frac{5.3}{100}\times1.93)$$

= $$14.08$$

=> Required % = $$\frac{14.08}{57.79}\times100\approx24.36\%$$

=> Ans - (D)

Number of children (in millions) not in school and not working in the category :

Rural females (10-14) = $$\frac{14}{100}\times13.42=1.88$$

Rural males (5-9) = $$\frac{31.5}{100}\times13.02=4.10$$

Rural females (5-9) = $$\frac{40.8}{100}\times15.63=6.37$$     [MAX]

Urban males (10-14) = $$\frac{5.8}{100}\times1.5=0.08$$

=> Ans - (C)

Number of children (in millions) not in school but working in the category :

Rural males (10-14) = $$\frac{12.8}{100}\times8.44=1.08$$

Rural females (10-14) = $$\frac{30.3}{100}\times13.42=4.06$$     [MAX]

Urban females (10-14) = $$\frac{13.1}{100}\times1.93=0.25$$

Urban males (10-14) = $$\frac{7}{100}\times1.5=0.10$$

=> Ans - (B)

Total child population not in school (in millions) = $$57.79$$

Total child population in school (in millions) = $$185.5-57.79=127.71$$

=> Required % ratio = $$\frac{127.71}{185.5}\times100$$

= $$68.87\%$$

=> Ans - (A)

Total child population not in school (in millions) = $$57.79$$

Total child population in school (in millions) = $$185.5-57.79=127.71$$

=> Required % ratio = $$\frac{57.79}{127.71}\times100$$

= $$45.20\%$$

=> Ans - (C)

Percentage of export with respect to production in the year

1992 = $$\frac{180}{540}\times100=33.33\%$$

1993 = $$\frac{288}{720}\times100=40\%$$

1996 = $$\frac{450}{660}\times100=68.19\%$$     [MAX]

1995 = $$\frac{400}{600}\times100=66.67\%$$

=> Ans - (C)

Tea available in India in 1993 = $$720-288=432$$ million kg

Per capita availability in 1993 = 0.4 kg

=> Population = $$\frac{432}{0.4}=1080$$ million

=> Ans - (B)

Since there is no data given about area, hence it cannot be determined.

=> Ans - (D)

Total tea exported (in millions kg) = 96+180+288+340+400+450 = 1754

Total tea produced (in millions kg) = 480+540+720+700+600+660 = 3700

=> Required ratio = $$\frac{1754}{3700}=0.47$$

=> Ans - (B)