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Side of the equilateral triangle = $$s=12$$ cm
=> Area of triangle = $$\triangle=\frac{\sqrt3}{4}s^2$$
= $$\frac{\sqrt3}{4}\times12\times12=36\sqrt3$$ $$cm^2$$
$$\therefore$$ Circumradius = $$R=\frac{abc}{4\triangle}$$
= $$\frac{12\times12\times12}{4\times36\sqrt3}$$
= $$\frac{12}{\sqrt3}=4\sqrt3$$ cm
=> Ans - (B)
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