Question 48

The radius of the circumcircle of an equilateral triangle of side 12 cm is

Solution

Side of the equilateral triangle = $$s=12$$ cm

=> Area of triangle = $$\triangle=\frac{\sqrt3}{4}s^2$$

= $$\frac{\sqrt3}{4}\times12\times12=36\sqrt3$$ $$cm^2$$

$$\therefore$$ Circumradius = $$R=\frac{abc}{4\triangle}$$

= $$\frac{12\times12\times12}{4\times36\sqrt3}$$

= $$\frac{12}{\sqrt3}=4\sqrt3$$ cm

=> Ans - (B)

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