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The distance between the tops of two trees 20 m and 28 m high is 17 m. The horizontal distance between the two trees is

AD and CE are two trees of height 28 m and 20 m respectively. AC = 17 m
In right $$\triangle$$ ABC,
=> $$(BC)^2=(AC)^2-(AB)^2$$
=> $$(BC)^2=(17)^2-(8)^2$$
=> $$(BC)^2=289-64=225$$
=> $$BC=\sqrt{225}=15$$ m
=> Ans - (C)
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