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Question 53

What least number must be subtracted from each of the numbers 14, 17, 34 and 42 so that the remainders are proportional ?

Solution

Let $$x$$ must be subtracted.

=> $$\frac{14-x}{17-x}=\frac{34-x}{42-x}$$

=> $$(14-x)(42-x)=(34-x)(17-x)$$

=> $$588-14x-42x+x^2=578-34x-17x+x^2$$

=> $$56x-51x=588-578$$

=> $$5x=10$$

=> $$x=2$$

=> Ans - (C)

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