You can find all the Top 77+ CAT Number Series questions from the previous papers with detailed video explanations on this page. The CAT Number Series plays a crucial role in CAT quantitative section. There are many tricks, shortcuts and formulas that help you to solve the questions quickly. One can find those solving tips in the video solutions explained by CAT experts and IIM Alumni. Click on the link below to download all the number system questions from CAT previous papers PDF. Keep practising free CAT mocks where you'll get a fair idea of how questions are asked, and type of questions asked.
The fundas of Number Series are important for other areas of CAT exam syllabus. To ace these kind of questions, aspirant must learn different approaches and practice. In such scenarios, getting a guidance from a CAT online coaching institute will help you in learning time saving approaches and strategies.
The below table provides the past 3 year weightage of Number Series questions in the CAT exam:
Year | No. of Questions |
| 2025 | 5 |
| 2024 | 5 |
| 2023 | 7 |
| 2022 | 5 |
1. A.G.P. Properties Formula
Arithmetic Geometric Series
A series will be an arithmetic-geometric series if each of its terms is formed by the product of the corresponding terms of an A.P and G.P.
The general form of A.G.P series is a, (a+d)r, (a+2d)$$r^{2}$$,......
Sum of ‘n’ terms of A.G.P series
$$S_{n}$$=$$\frac{a}{1-r}$$+rd$$\frac{(1-r^{n-1})}{1-r}$$+rn$$\frac{[a+(n-1)d]}{1-r}$$(r≠1)
Sum of infinite terms of A.G.P series
$$S_{∞}$$=$$\frac{a}{1-r}+\frac{dr}{(1-r)^{2}}$$(|r|<1)
2. G.P. - Formulas and Properties
Geometric Progression
If in a succession of numbers the ratio of any term and the previous term is constant then that numbers are said to be in Geometric Progression.
Ex :1, 3, 9, 27 or a, ar, a$$r^{2}$$, a$$r^{3}$$
The general expression of a G.P, Tn = a $$r^{n-1}$$ (where a is the first term and ‘r’ is the common ratio).
Sum of ‘n’ terms in G.P, Sn = $$\frac{a(1-r^{n})}{1-r}$$ (if r<1) or $$\frac {a(r^{n}-1)}{r-1}$$ (if r>1)
Properties of G.P
If a, b , c, d,.... are in G.P and ‘k’ is a constant then
Sum of term of infinite series in G.P, $$S_{∞}$$=$$\frac {a}{1-r}$$ (-1 < r <1)
3. A.P. - Formulas and Properties
Arithmetic progression (A.P)
If the sum of the difference between any two consecutive terms is constant then the terms are said to be in A.P
Example: 2,5,8,11 or a, a+d, a+2d, a+3d...
If 'a' is the first term and 'd' is a common difference then the general 'n' term is $$T_{n}$$=a+(n-1)d
Sum of first 'n' terms in A.P=$$\frac{n}{2}$$[2a+(n-1)d]
Number of terms in A.P=$$\frac{Last Term-First Term}{Common Difference}$$+1
Properties of Arithmetic progression
If a, b, c, d,.... are in A.P and ‘k’ is a constant then
a-k, b-k, c-k,... will also be in A.P
ak, bk, ck,...will also be in A.P
a/k, b/k, c/k will also be in A.P
4. Harmonic Mean Formula
Harmonic Mean
If a, b, c, d...are the given numbers in H.P then the Harmonic mean of 'n' terms=$$\frac{Number of terms}{\frac{1}{a}+\frac{1}{a}+\frac{1}{a}+....}$$
If two numbers a and b are in H.P then the Harmonic mean= $$\frac{2ab}{a+b}$$
The average number of copies of a book sold per day by a shopkeeper is 60 in the initial seven days and 63 in the initial eight days, after the book launch. On the ninth day, she sells 11 copies less than the eighth day, and the average number of copies sold per day from second day to ninth day becomes 66. The number of copies sold on the first day of the book launch is
correct answer:-49
In an arithmetic progression, if the sum of fourth, seventh and tenth terms is 99, and the sum of the first fourteen terms is 497, then the sum of first five terms is
correct answer:-65
For any natural number k , let $$a_{k}=3^{k}$$. The smallest natural number m for which $$\left\{(a_{1})^{1}\times(a_{2})^{2}\times...\times(a_{20})^{20}\right\}<\left\{a_{21}\times a_{22}\times...\times a_{20+m}\right\}$$, is
correct answer:-1
In the set of consecutive odd numbers $$\left\{1,3,5,...,57\right\}$$, there is a number $$k$$ such that the sum of all the elements less than $$k$$ is equal to the sum of all the elements greater than $$k$$ . Then, $$k$$ equals
correct answer:-1
Let $$a_{n}$$ be the $$n^{th}$$ term of a decreasing infinite geometric progression. If $$a_{1}+a_{2}+a_{3}=52$$ and $$a_{1}a_{2}+a_{2}a_{3}+a_{3}a_{1}=624$$, then the sum of this geometric progression is
correct answer:-2
Suppose $$x_{1},x_{2},x_{3},...,x_{100}$$ are in arithmetic progression such that $$x_{5}=-4$$ and $$2x_{6}+2x_{9}=x_{11}+x_{13}$$, Then,$$x_{100}$$ equals
correct answer:-1
Consider the sequence $$t_1 = 1, t_2 = -1$$ and $$t_n = \left(\cfrac{n - 3}{n - 1}\right)t_{n - 2}$$ for $$n \geq 3$$. Then, the value of the sum $$\cfrac{1}{t_2} + \cfrac{1}{t_4} + \cfrac{1}{t_6} + ....... +\cfrac{1}{t_{2022}} + \cfrac{1}{t_{2024}}$$, is
correct answer:-1
For any natural number $$n$$ let $$a_{n}$$ be the largest integer not exceeding $$\sqrt{n}$$. Then the value of $$a_{1}+a_{2}+.....+a_{50}$$ is
correct answer:-217
The sum of the infinite series $$\cfrac{1}{5}\left(\cfrac{1}{5} - \cfrac{1}{7}\right) + \left(\cfrac{1}{5}\right)^2 \left(\left(\cfrac{1}{5}\right)^2 - \left(\cfrac{1}{7}\right)^2\right) + \left(\cfrac{1}{5}\right)^3 \left(\left(\cfrac{1}{5}\right)^3 - \left(\cfrac{1}{7}\right)^3\right) + ......$$ is equal to
correct answer:-2
For a real number x, if $$\frac{1}{2}, \frac{\log_3(2^x - 9)}{\log_3 4}$$, and $$\frac{\log_5\left(2^x + \frac{17}{2}\right)}{\log_5 4}$$ are in an arithmetic progression, then the common difference is
correct answer:-4
For some positive and distinct real numbers $$x, y$$ and z, if $$\frac{1}{\sqrt{y}+\sqrt{z}}$$ is the arithmetic mean of $$\frac{1}{\sqrt{x}+\sqrt{z}}$$ and $$\frac{1}{\sqrt{x}+\sqrt{y}}$$, then the relationship which will always hold true, is
correct answer:-2
Let both the series $$a_{1},a_{2},a_{3}$$... and $$b_{1},b_{2},b_{3}$$... be in arithmetic progression such that the common differences of both the series are prime numbers. If $$a_{5}=b_{9},a_{19}=b_{19}$$ and $$b_{2}=0$$, then $$a_{11}$$ equals
correct answer:-2
The value of $$1 + \left(1 + \frac{1}{3}\right)\frac{1}{4} + \left(1 + \frac{1}{3} + \frac{1}{9}\right)\frac{1}{16} + \left(1 + \frac{1}{3} + \frac{1}{9} + \frac{1}{27}\right)\frac{1}{64} + -------$$ is
correct answer:-4
Let $$a_n = 46 + 8n$$ and $$b_n = 98 + 4n$$ be two sequences for natural numbers $$n \leq 100$$. Then, the sum of all terms common to both the sequences is
correct answer:-1
A lab experiment measures the number of organisms at 8 am every day. Starting with 2 organisms on the first day, the number of organisms on any day is equal to 3 more than twice the number on the previous day. If the number of organisms on the nth day exceeds one million, then the lowest possible value of n is
correct answer:-19
Let $$a_{n}$$ and $$b_{n}$$ be two sequences such that $$a_{n}=13+6(n-1)$$ and $$b_{n}=15+7(n-1)$$ for all natural numbers n. Then, the largest three digit integer that is common to both these sequences, is
correct answer:-967
The average of a non-decreasing sequence of N numbers $$a_{1},a_{2}, ... , a_{N}$$ is 300. If $$a_1$$, is replaced by $$6a_{1}$$ , the new average becomes 400. Then, the number of possible values of $$a_{1 }$$, is
correct answer:-14
For any natural number n, suppose the sum of the first n terms of an arithmetic progression is $$(n + 2n^2)$$. If the $$n^{th}$$ term of the progression is divisible by 9, then the smallest possible value of n is
correct answer:-3
On day one, there are 100 particles in a laboratory experiment. On day n, where $$n\ge2$$, one out of every n articles produces another particle. If the total number of particles in the laboratory experiment increases to 1000 on day m, then m equals
correct answer:-1
The average of all 3-digit terms in the arithmetic progression 38, 55, 72, ..., is
correct answer:-548