SRCC GBO 2024

From the table, we can see that in the year 2018-2019, Company D shows (25/135)*100% = 18.52% increase in market value, which is higher than any other changes.

The correct option is C

The absolute change in the market value (year wise) are given in the table below:

From the table, we can see that the greatest absolute change in market share occurred for Company A in the year 2019-20

Hence, the correct option is C

It is given that the ratio of the students in institution A to that of institution B is 7 : 8, which implies if the students in institution A is 7x, then the students in institution B is 8x.

It is also known that the total number of students in both institutions are 1350.

=> (7x+8x) = 1350 => x = 90

Thus, the students in institution A is (7*90) = 630, and the students in institution B is (8*90) = 720

It is given that In institution A, 70% students are boys and the rest are girls, whereas in institution B the ratio of boys to girls is 11 : 7.

Thus, the number of boys in institution A = (70% of 630) = 441, and the number of girls in institution A = (630-441) = 189.

Similarly, the number of boys in institution B = (11/18)*720 = 440, and the number of girls in institution B = (720-440) = 280

It is given that there are only three classes in each Institution, Class X, Class Y and Class Z.

It is known that in institution A, (4/7)th of the total girls joined Class Y, which implies the total number of girls at Class Y in institution A is (4/7)*189 = 108, which implies the remaining number of girls = (189-108) = 81. It is also known that (5/9)th of the remaining girls enrolled in Class Z and rest in Class X.

Thus, the total number of girls at Class Z in institution A is (5/9)*81 = 45 =>  the total number of girls at Class X in institution A is (81-45) = 36

Now, in institution A, the total number of boys at Class X = (3/7)* 441 = 189, which implies the number of boys who are remaining is (441-189) = 252

It is given that (4/9) of the remaining boys are in Class Y = (4/9)*252 = 112, and the boys in class Z in institution A = (252-112) = 140

Now, in Institution B, (4/11)th of the boys are in Class Y = (4/11)*440 = 160, and the number of boys in Class Z is (21/20)*160 = 168, which means the number of boys in Class X = (440-160-168) = 112

Similarly, (1/4)th of the girls are in Class Z = (1/4)*280 = 70, and it is given that the number of girls enrolled in class X is 10% more than the girls enrolled in class Y.

Let the number of girls in Class Y be 100x, which implies the number of girls in Class X is 110x

Thus, (110x+100x) = 210 => x = 1 => The number of girls in Class Y is 100, and the number of girls in Class X is 110

We know that the number of boys enrolled in class X in institution A is 189, and the number of girls enrolled in class Y in institution B = 100

Thus, the number of boys enrolled in class X in institution A is 89% more than the number of girls enrolled in class Y in institution B.

The correct option is B

It is given that the ratio of the students in institution A to that of institution B is 7 : 8, which implies if the students in institution A is 7x, then the students in institution B is 8x.

It is also known that the total number of students in both institutions are 1350.

=> (7x+8x) = 1350 => x = 90

Thus, the students in institution A is (7*90) = 630, and the students in institution B is (8*90) = 720

It is given that In institution A, 70% students are boys and the rest are girls, whereas in institution B the ratio of boys to girls is 11 : 7.

Thus, the number of boys in institution A = (70% of 630) = 441, and the number of girls in institution A = (630-441) = 189.

Similarly, the number of boys in institution B = (11/18)*720 = 440, and the number of girls in institution B = (720-440) = 280

It is given that there are only three classes in each Institution, Class X, Class Y and Class Z.

It is known that in institution A, (4/7)th of the total girls joined Class Y, which implies the total number of girls at Class Y in institution A is (4/7)*189 = 108, which implies the remaining number of girls = (189-108) = 81. It is also known that (5/9)th of the remaining girls enrolled in Class Z and rest in Class X.

Thus, the total number of girls at Class Z in institution A is (5/9)*81 = 45 => the total number of girls at Class X in institution A is (81-45) = 36

Now, in institution A, the total number of boys at Class X = (3/7)* 441 = 189, which implies the number of boys who are remaining is (441-189) = 252

It is given that (4/9) of the remaining boys are in Class Y = (4/9)*252 = 112, and the boys in class Z in institution A = (252-112) = 140

Now, in Institution B, (4/11)th of the boys are in Class Y = (4/11)*440 = 160, and the number of boys in Class Z is (21/20)*160 = 168, which means the number of boys in Class X = (440-160-168) = 112

Similarly, (1/4)th of the girls are in Class Z = (1/4)*280 = 70, and it is given that the number of girls enrolled in class X is 10% more than the girls enrolled in class Y.

Let the number of girls in Class Y be 100x, which implies the number of girls in Class X is 110x

Thus, (110x+100x) = 210 => x = 1 => The number of girls in Class Y is 100, and the number of girls in Class X is 110

Hence, the total number of students enrolled in class Y of both institutions = (number of boys in class Y in both institutions) + (number of girls in Class Y in both institutions)

=> (112+160)+(108+100) = 480

The correct option is C

It is given that the ratio of the students in institution A to that of institution B is 7 : 8, which implies if the students in institution A is 7x, then the students in institution B is 8x.

It is also known that the total number of students in both institutions are 1350.

=> (7x+8x) = 1350 => x = 90

Thus, the students in institution A is (7*90) = 630, and the students in institution B is (8*90) = 720

It is given that In institution A, 70% students are boys and the rest are girls, whereas in institution B the ratio of boys to girls is 11 : 7.

Thus, the number of boys in institution A = (70% of 630) = 441, and the number of girls in institution A = (630-441) = 189.

Similarly, the number of boys in institution B = (11/18)*720 = 440, and the number of girls in institution B = (720-440) = 280

It is given that there are only three classes in each Institution, Class X, Class Y and Class Z.

It is known that in institution A, (4/7)th of the total girls joined Class Y, which implies the total number of girls at Class Y in institution A is (4/7)*189 = 108, which implies the remaining number of girls = (189-108) = 81. It is also known that (5/9)th of the remaining girls enrolled in Class Z and rest in Class X.

Thus, the total number of girls at Class Z in institution A is (5/9)*81 = 45 => the total number of girls at Class X in institution A is (81-45) = 36

Now, in institution A, the total number of boys at Class X = (3/7)* 441 = 189, which implies the number of boys who are remaining is (441-189) = 252

It is given that (4/9) of the remaining boys are in Class Y = (4/9)*252 = 112, and the boys in class Z in institution A = (252-112) = 140

Now, in Institution B, (4/11)th of the boys are in Class Y = (4/11)*440 = 160, and the number of boys in Class Z is (21/20)*160 = 168, which means the number of boys in Class X = (440-160-168) = 112

Similarly, (1/4)th of the girls are in Class Z = (1/4)*280 = 70, and it is given that the number of girls enrolled in class X is 10% more than the girls enrolled in class Y.

Let the number of girls in Class Y be 100x, which implies the number of girls in Class X is 110x

Thus, (110x+100x) = 210 => x = 1 => The number of girls in Class Y is 100, and the number of girls in Class X is 110

Therefore,  the number of boys enrolled in Class Y in institution B = 160, and the number of girls enrolled in Class X in institution A = 36.

Hence, the difference is (160-36) = 124

The correct option is D

It is given that the ratio of the students in institution A to that of institution B is 7 : 8, which implies if the students in institution A is 7x, then the students in institution B is 8x.

It is also known that the total number of students in both institutions are 1350.

=> (7x+8x) = 1350 => x = 90

Thus, the students in institution A is (7*90) = 630, and the students in institution B is (8*90) = 720

It is given that In institution A, 70% students are boys and the rest are girls, whereas in institution B the ratio of boys to girls is 11 : 7.

Thus, the number of boys in institution A = (70% of 630) = 441, and the number of girls in institution A = (630-441) = 189.

Similarly, the number of boys in institution B = (11/18)*720 = 440, and the number of girls in institution B = (720-440) = 280

It is given that there are only three classes in each Institution, Class X, Class Y and Class Z.

It is known that in institution A, (4/7)th of the total girls joined Class Y, which implies the total number of girls at Class Y in institution A is (4/7)*189 = 108, which implies the remaining number of girls = (189-108) = 81. It is also known that (5/9)th of the remaining girls enrolled in Class Z and rest in Class X.

Thus, the total number of girls at Class Z in institution A is (5/9)*81 = 45 => the total number of girls at Class X in institution A is (81-45) = 36

Now, in institution A, the total number of boys at Class X = (3/7)* 441 = 189, which implies the number of boys who are remaining is (441-189) = 252

It is given that (4/9) of the remaining boys are in Class Y = (4/9)*252 = 112, and the boys in class Z in institution A = (252-112) = 140

Now, in Institution B, (4/11)th of the boys are in Class Y = (4/11)*440 = 160, and the number of boys in Class Z is (21/20)*160 = 168, which means the number of boys in Class X = (440-160-168) = 112

Similarly, (1/4)th of the girls are in Class Z = (1/4)*280 = 70, and it is given that the number of girls enrolled in class X is 10% more than the girls enrolled in class Y.

Let the number of girls in Class Y be 100x, which implies the number of girls in Class X is 110x

Thus, (110x+100x) = 210 => x = 1 => The number of girls in Class Y is 100, and the number of girls in Class X is 110

Hence, the total number of boys enrolled in classes X and Y in institution A = (189+112) = 301, and the number of girls enrolled in classes Y and Z in institution B = (100+70) = 170

Therefore, the total number of boys enrolled in classes X and Y in institution A is (301/170)*100% = 177%

The correct option is A

In the above given bar graphs the population and national income of a country from the fiscal years 2014-15 to 2019-20 are shown.

Let us tabulate the above information from the graph into a table and also calculate per capita income for all the fiscal years.

On the basis of the above table

We need to find the year the increase in per capita income compared to the previous years is the lowest.

Let us check for each option and calculate the increase in per capita income compared to previous years for the following fiscal years.

Option A) 2015-2016

The difference in per capita income for years 2015-2016 and 2014-2015 is approximately equal to 3482-3098 = 384

Option B) 2019-2020

The difference in per capita income for years 2019-2020 and 2018-2019 is approximately equal to 5319-4857 = 462

Option C) 2017-2018

The difference in per capita income for years 2017-2018 and 2016-2017 is approximately equal to 4221-3786 = 435

Option D) 2016-2017

The difference in per capita income for years 2016-2017 and 2015-2016 is approximately equal to 3786-3482 = 304

Hence, the lowest increase in per capita income compared to previous year is in the fiscal year 2016-2017. (Option D)

In the above given bar graphs the population and national income of a country from the fiscal years 2014-15 to 2019-20 are shown.

Let us tabulate the above information from the graph into a table and also calculate per capita income for all the fiscal years.

On the basis of the above table

We need to find the year in which the difference between the percentage increase in per capital income and the percentage increase in population compared to the previous year the highest.

Let us check for each option and calculate the difference of % increase in per capita income and % increase in population compared to previous years for the following fiscal years.

Option A) 2017-2018

The % increase in per capita income in the year 2017-2018 as compared to 2016-2017 is

=> (4221-3786)/3786= 11.49%

The % increase in population in the year 2017-2018 as compared to 2016-2017 is

=> (117.25-115.5)/115.5 = 1.52%

Thus, the difference between them = 11.49-1.52 = 9.97

Option B) 2015-2016

The % increase in per capita income in the year 2015-2016 as compared to 2014-2015 is

=> (3482-3098)/3098 = 12.40%

The % increase in population in the year 2015-2016 as compared to 2014-2015 is

=>(112.5-111)/111 = 1.35%

Thus, the difference between them = 12.40-1.35 = 11.05

Option C) 2016-2017

The % increase in per capita income in the year 2016-2017 as compared to 2015-2016 is

=> (3786-3482)/3482 = 8.73%

The % increase in population in the year 2016-2017 as compared to 2015-2016 is

=> (115.5-112.5)/112.5 = 2.66%

Thus, the difference between them = 8.73-2.66 = 6.07

Option D) 2018-2019

The % increase in per capita income in the year 2018-2019 as compared to 2017-2018 is

=> (4857-4221)/4221 = 15.06%

The % increase in population in the year 2018-2019 as compared to 2017-2018 is

=> (120-117.25)/117.25 = 2.34%

Thus, the difference between them = 15.06-2.34 = 12.72

Thus, the difference between the percentage increase in per capital income and the percentage increase in population compared to the previous year the highest for the year 2018-2019. (Option D)

In the above given bar graphs the population and national income of a country from the fiscal years 2014-15 to 2019-20 are shown.

Let us tabulate the above information from the graph into a table and also calculate per capita income for all the fiscal years.

On the basis of the above table

In the above given bar graphs the population and national income of a country from the fiscal years 2014-15 to 2019-20 are shown.

Let us tabulate the above information from the graph into a table and also calculate per capita income for all the fiscal years.

On the basis of the above table

We need to find the year which witnessed the highest increase in per capita income compared to the previous year.

Let us check for each option and calculate the increase in per capita income compared to previous years for the following fiscal years.

Option A) 2016-2017

The difference in per capita income for years 2016-2017 and 2015-2016 is approximately equal to 3786-3482 = 304

Option B) 2017-2018

The difference in per capita income for years 2017-2018 and 2016-2017 is approximately equal to 4221-3786 = 435

Option C) 2015-2016

The difference in per capita income for years 2015-2016 and 2014-2015 is approximately equal to 3482-3098 = 384

Option D) 2018-2019

The difference in per capita income for years 2018-2019 and 2017-2018 is approximately equal to 4857-4221 = 636

Hence, the highest increase in per capita income compared to previous year is in the fiscal year 2018-2019. (Option D)