Question 106

The least perfect square that is divisible by each of 321, 48 and 66 is:

Solution

Slit the given numbers as follows.

321 - 107*3

48 - $$2^4$$*3

66 - 11*2*3

To have a perfect square, we need to have even powers to the prime numbers. That is $$2^4\cdot107^2\cdot11^2\cdot3^2$$. That will be $$16 \times 1089 \times 11449 $$.


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