The least perfect square that is divisible by each of 321, 48 and 66 is:
Solution
Slit the given numbers as follows.
321 - 107*3
48 - $$2^4$$*3
66 - 11*2*3
To have a perfect square, we need to have even powers to the prime numbers. That is $$2^4\cdot107^2\cdot11^2\cdot3^2$$. That will be $$16 \times 1089 \times 11449 $$.