Question 147

A man walks 10 m south. Then turning to his right, he walks 12 m. Then turning to his left, he walks 8 m. Again, he turns to his left and walks 5 m. How far is he from his initial position?

Solution

The formed right-angled triangle is having base 18(10+8) and height 7(12-5).

The distance is $$\sqrt{\ 18^2+7^2}=\sqrt{\ 373}$$


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