Sign in
Please select an account to continue using cracku.in
↓ →
A man walks 10 m south. Then turning to his right, he walks 12 m. Then turning to his left, he walks 8 m. Again, he turns to his left and walks 5 m. How far is he from his initial position?
The formed right-angled triangle is having base 18(10+8) and height 7(12-5).
The distance is $$\sqrt{\ 18^2+7^2}=\sqrt{\ 373}$$
Book Free CAT Mentorship
Get personalized CAT strategy from a 99%iler
500+ students mentored
OTP Verification
Enter the 6-digit code sent to your phone
Booking Summary
Enter OTP
Didn't receive the OTP?
Start your IIM journey with the right preparation and crack CAT 2026.
Educational materials for CAT preparation